[LeetCode] Product of Array Except Self
Updated:
문제
Given an integer array nums
, return an array answer
such that answer[i]
is equal to the product of all the elements of nums
except nums[i]
.
The product of any prefix or suffix of nums
is guaranteed to fit in a 32-bit integer.
예제
Example 1:
Input: nums = [1,2,3,4]
Output: [24,12,8,6]
Example 2:
Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]
조건
- 2 <= nums.length <= $10^5$
- -30 <= nums[i] <= 30
- The product of any prefix or suffix of
nums
is guaranteed to fit in a 32-bit integer.
답
풀이 1
class Solution:
def productExceptSelf(self, nums: List[int]) -> List[int]:
answer1 = [1 for _ in range(len(nums))]
answer2 = [1 for _ in range(len(nums))]
for n in range(len(nums)-1):
answer1[n+1] = answer1[n]*nums[n]
for n in range(len(nums)-1,0,-1):
answer2[n-1] = answer2[n]*nums[n]
answer = [1 for _ in range(len(nums))]
for n in range(len(nums)):
answer[n] = answer1[n]*answer2[n]
return answer
Leave a comment