[LeetCode] Subsets
Updated:
문제
Given an integer array nums
of unique elements, return all possible subsets (the power set).
The solution set must not contain duplicate subsets. Return the solution in any order.
예제
Example 1:
Input: nums = [1,2,3]
Output: [[],[1],[2],[1,2],[3],[1,3],[2,3],[1,2,3]]
Example 2:
Input: nums = [0]
Output: [[],[0]]
조건
1 <= nums.length <= 10
-10 <= nums[i] <= 10
- All the numbers of
nums
are unique.
답
풀이 1
BFS를 활용한 풀이
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
ans = []
sub = []
q = collections.deque()
q.append([sub, -1])
while q:
li, index = q.popleft()
ans.append(li)
if index == len(nums) - 1:
continue
for i in range(index+1, len(nums)):
q.append([li+[nums[i]], i])
return ans
풀이 2
DFS를 활용한 풀이
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
result = []
def dfs(index, path):
# 매번 결과 추가
result.append(path)
# 경로를 만들면서 DFS
for i in range(index, len(nums)):
dfs(i + 1, path + [nums[i]])
dfs(0, [])
return result
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